-16x^2+96x+2.5=0

Solution for -16x^2+96x+2.5=0 equation:

-16x^2+96x+2.5=0

a = -16; b = 96; c = +2.5;
Δ = b2-4ac
Δ = 962-4·(-16)·2.5
Δ = 9376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9376}=\sqrt{16*586}=\sqrt{16}*\sqrt{586}=4\sqrt{586}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-4\sqrt{586}}{2*-16}=\frac{-96-4\sqrt{586}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+4\sqrt{586}}{2*-16}=\frac{-96+4\sqrt{586}}{-32}
$